Symcli Questions

» How to Terminate a clone session ?

  • symclone -g TestDg terminate DEV001 sym ld DEV002
    Description: This will terminate the clone session between DEV001 and DEV002, deletes the pairing information from the storage array and removes any hold on target device.You have to 'Terminate' while the pair in 'Copied' state to get a fully valid data.

Related Questions :

  • symmir -g TestDg cancel
    Description: Terminate the relationship between the standard and BCV devices in device group TestDg.

  • symconfigure -sid 1234 abort
    Description: Abort a configuration session started earlier.

  • symclone -g TestDg create DEV001 sym ld DEV002
    Description: Create a clone copy session between the devices DEV001(source) and DEV002(target) in regular diskgroup TestDg. By default this will create a differentail session.That means, we can do a incremental recreate or restore later.This command will make the target device in Not Ready(NR).

  • symclone -g TestDg create DEV001 sym ld DEV002 -precopy
    Description: Create a clone copy session between the devices DEV001(source) and DEV002(target) in regular diskgroup TestDg. This will start background copy from DEV001 to DEV002 after making the target device as NotReady(NR).

  • symclone -g TestDg create DEV001 sym ld DEV002 -nocopy
    Description: Create a "CopyOnAccess" clone session between the devices DEV001(source) and DEV002(target) in regular diskgroup TestDg.This wont start any background copying from source to target device even after activating the session.


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